• Year
  • 1958/1959
  • Category
  • Broadcast Receiver - or past WW2 Tuner
  • Radiomuseum.org ID
  • 75954

Click on the schematic thumbnail to request the schematic as a free document.

 Technical Specifications

  • Number of Tubes
  • 5
  • Main principle
  • Superheterodyne (common); ZF/IF 452 kHz
  • Wave bands
  • Broadcast plus 2 Short Wave bands.
  • Power type and voltage
  • AC/DC-set / 110, 127, 220 Volt
  • Loudspeaker
  • Permanent Magnet Dynamic (PDyn) Loudspeaker (moving coil)
  • Material
  • Bakelite case
  • from Radiomuseum.org
  • Model: B2X85U - Philips; Eindhoven tubes
  • Shape
  • Tablemodel, with any shape - general.
  • Dimensions (WHD)
  • 316 x 180 x 150 mm / 12.4 x 7.1 x 5.9 inch
  • Notes
  • Dial lamp: 8009D (6,3V/0,25A)
  • Author
  • Model page created by Petros Tsirvoulis. See "Data change" for further contributors.

 Collections | Museums | Literature


The model is part of the collections of the following members.


Forum contributions about this model: Philips; Eindhoven: B2X85U

Threads: 1 | Posts: 4

I am restoring a radio Philips B2X85U (or B2K85U). I've got the schematics but I can not realize where to connect the 2 new capacitors in the place of the original can.

I mean, I have 2 capacitors with 4 leads and the PCB of the radio has 5 connection points on the original can.

I guess that the  2 negatives leads have a rail for both of them. Still, I have 4 connection for the other two positive leads.

There is a divider resistor that can solve one lead in two connections but the other positive lead will have to go to the other two connection points?

The pictures will show it.

What I need to know is where I can solder the 4 new leads?


Alvaro Georg 

YouTube: Rádios Antigos & Cia Ltda




Alvaro Georg, 11.Jan.21

Weitere Posts (4) zu diesem Thema.